(4)-(3/k)-(1/k^2)=0

Solution for (4)-(3/k)-(1/k^2)=0 equation:

D( k )

k^2 = 0

k = 0

k^2 = 0

k^2 = 0

1*k^2 = 0 // : 1

k^2 = 0

k = 0

k = 0

k = 0

k in (-oo:0) U (0:+oo)

4-(3/k)-(1/(k^2)) = 0

4-3*k^-1-k^-2 = 0

t_1 = k^-1

4-1*t_1^2-3*t_1^1 = 0

4-t_1^2-3*t_1 = 0

DELTA = (-3)^2-(-1*4*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+3)/(-1*2) or t_1 = (3-25^(1/2))/(-1*2)

t_1 = -4 or t_1 = 1

t_1 = -4

k^-1+4 = 0

1*k^-1 = -4 // : 1

k^-1 = -4

-1 < 0

1/(k^1) = -4 // * k^1

1 = -4*k^1 // : -4

-1/4 = k^1

k = -1/4

t_1 = 1

k^-1-1 = 0

1*k^-1 = 1 // : 1

k^-1 = 1

-1 < 0

1/(k^1) = 1 // * k^1

1 = 1*k^1 // : 1

1 = k^1

k = 1

k in { -1/4, 1 }